5b^2+27b+28=0

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Solution for 5b^2+27b+28=0 equation:


Simplifying
5b2 + 27b + 28 = 0

Reorder the terms:
28 + 27b + 5b2 = 0

Solving
28 + 27b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + b)(7 + 5b) = 0

Subproblem 1

Set the factor '(4 + b)' equal to zero and attempt to solve: Simplifying 4 + b = 0 Solving 4 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + b = 0 + -4 b = 0 + -4 Combine like terms: 0 + -4 = -4 b = -4 Simplifying b = -4

Subproblem 2

Set the factor '(7 + 5b)' equal to zero and attempt to solve: Simplifying 7 + 5b = 0 Solving 7 + 5b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 5b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 5b = 0 + -7 5b = 0 + -7 Combine like terms: 0 + -7 = -7 5b = -7 Divide each side by '5'. b = -1.4 Simplifying b = -1.4

Solution

b = {-4, -1.4}

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